Ind The Area Of The Part Of The Circle R=4sin+Cos In The Fourth Quadrant.

Ind The Area Of The Part Of The Circle R=4sin+Cos In The Fourth Quadrant

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Introduction to the Problem

In the realm of coordinate geometry and polar equations, understanding the area enclosed by specific parts of curves is a fundamental concept. The problem of finding the area of a particular segment or sector of a circle defined by a polar equation is common in advanced mathematics, physics, and engineering applications. In this article, we focus on calculating the area of the part of the circle given by the polar equation R = 4sinθ + cosθ that resides specifically in the fourth quadrant.

This exploration involves translating the polar equation into a more familiar Cartesian form, identifying the relevant angular ranges, and then applying the appropriate integral calculus techniques to compute the area. By the end of this discussion, readers will understand the step-by-step process involved in solving such problems, along with insights into the geometric interpretation of the results.

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Understanding the Polar Equation R = 4sinθ + Cosθ

What Is a Polar Equation?

A polar equation describes a curve in the plane using a radius (R) and an angle (θ). For each value of θ, the radius R specifies how far from the origin the point lies. The equation R = 4sinθ + cosθ combines sine and cosine functions, resulting in a curve that exhibits certain symmetries and properties.

Analyzing R = 4sinθ + Cosθ

This particular equation can be rewritten to better understand its geometric nature:


  • Recognize that R = a sinθ + b cosθ can be expressed as R = √(a² + b²) sin(θ + α), where α is an angle satisfying certain conditions.

  • For R = 4sinθ + cosθ:

  • a = 4

  • b = 1

  • Compute the amplitude:


√(4² + 1²) = √(16 + 1) = √17 ≈ 4.1231

  • Find the phase shift α:


α = arctangent(b / a) = arctangent(1 / 4) ≈ 14.04°

This form indicates that the original curve is a sinusoidally shifted circle or a similar conic, which helps in visualizing and calculating the area.

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Geometric Interpretation of the Curve

Shape and Symmetry

The equation R = 4sinθ + cosθ describes a circle in the polar coordinate system. To confirm this, we can convert it to Cartesian coordinates or analyze its properties:


  • Using the identities:

  • x = R cosθ

  • y = R sinθ

  • Substituting R:

  • x = (4sinθ + cosθ) cosθ

  • y = (4sinθ + cosθ) sinθ

  • Alternatively, it might be more straightforward to convert the polar form into Cartesian form directly.


Conversion to Cartesian Coordinates

Starting from the polar equation:

R = 4sinθ + cosθ

Express R in terms of x and y:


  • R² = x² + y²

  • cosθ = x / R

  • sinθ = y / R


Substitute into the original equation:

R = 4(y / R) + (x / R)

Multiply both sides by R:

R² = 4y + x

Replace R² with x² + y²:

x² + y² = 4y + x

Bring all terms to one side:

x² + y² - 4y - x = 0

Complete the square for x and y:


  • For x:


x² - x = (x - 0.5)² - 0.25

  • For y:


y² - 4y = (y - 2)² - 4

Rewrite the equation:

(x - 0.5)² - 0.25 + (y - 2)² - 4 = 0

Combine constants:

(x - 0.5)² + (y - 2)² = 4.25

This is the equation of a circle with:


  • Center at (0.5, 2)

  • Radius √4.25 ≈ 2.0616


Visualizing the Circle

The circle's position and size are now clear:


  • Located near the point (0.5, 2)

  • With a radius of approximately 2.06 units


Understanding the circle's position helps determine which parts lie in the fourth quadrant.

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Identifying the Fourth Quadrant Segment

Definition of the Fourth Quadrant

In Cartesian coordinates, the fourth quadrant is where:


  • x > 0

  • y < 0


In polar coordinates, the fourth quadrant corresponds to:

  • θ between 270° (3π/2) and 360° (2π)


or in radians:

  • θ in (3π/2, 2π)


Angular Range for the Part in the Fourth Quadrant

Since the circle is centered at (0.5, 2), which is above the x-axis, and has a radius of approximately 2.06, parts of it will extend into the fourth quadrant depending on its position.

To find the exact angular range:


  • Determine the points where the circle intersects the x-axis (y=0), which are critical in defining the segment.


Substitute y=0 into the circle's equation:

(x - 0.5)² + (0 - 2)² = 4.25

Simplify:

(x - 0.5)² + 4 = 4.25

(x - 0.5)² = 0.25

x - 0.5 = ±0.5

x = 0 or x = 1

Corresponding points:


  • (0, 0): at the origin

  • (1, 0): at x=1, y=0


Now, consider the angles θ corresponding to these points:

  • For (0, 0):


r = √(0² + 0²) = 0

θ is undefined, but the point is at the origin.


  • For (1, 0):


r = 1

θ = arctangent(0 / 1) = 0°

Since θ=0 corresponds to the positive x-axis, the points of intersection are at:


  • (1, 0): θ=0°, r=1

  • (0, 0): at the origin, which is the intersection point of the circle and the x-axis.


Given the circle's center at (0.5, 2), and radius approximately 2.06, the circle extends into the fourth quadrant near θ approaching 2π, but precise calculation involves solving for the angles at which the circle intersects the axes.

Calculating the Sector Area

To find the area of the part of the circle lying in the fourth quadrant:


  1. Identify the angular limits (θ1 and θ2) corresponding to the intersection points of the circle with the axes or with lines y=0 and x>0.

  2. Determine whether the circle extends into the fourth quadrant based on these points.

  3. Use the polar area formula:


\[
A = \frac{1}{2} \int{\theta1}^{\theta_2} R^2 \, d\theta
\]

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Computing the Area in the Fourth Quadrant

Step 1: Find the Relevant Angular Limits

Given the circle's Cartesian equation:

\[
(x - 0.5)^2 + (y - 2)^2 = 4.25
\]

Expressed in polar coordinates:

\[
x = R \cos\theta \\
y = R \sin\theta
\]

Substitute into the circle's equation:

\[
(R \cos\theta - 0.5)^2 + (R \sin\theta - 2)^2 = 4.25
\]

Expanding:

\[
R^2 \cos^2\theta - R \cos\theta + 0.25 + R^2 \sin^2\theta - 4 R \sin\theta + 4 = 4.25
\]

Combine like terms:

\[
R^2 (\cos^2\theta + \sin^2\theta) - R (\cos\theta + 4 \sin\theta) + (0.25 + 4) = 4.25
\]

Since \(\cos^2\theta + \sin^2\theta = 1\):

\[
R^2 - R (\cos\theta + 4 \sin\theta) + 4.25 = 4.25
\]

Subtract 4.25 from both sides:

\[
R^2 - R (\cos\theta + 4 \sin\theta) = 0
\]

Factor:

\[
R [ R - (\cos\theta + 4 \sin\theta) ] = 0
\]

Thus, either:


  • R = 0, which corresponds to the origin, or

  • \( R = \cos\theta + 4 \sin\theta \)


Recall that R = 4 sinθ + cosθ, so the second solution matches the original equation, confirming the points on the circle.

Step 2: Find the θ Values at the Intersection Points

At the intersection with the axes, the radius R is zero:

\[
0 = 4 \sin

Frequently Asked Questions

What is the equation of the curve in the fourth quadrant for R = 4sinθ + cosθ?
In the fourth quadrant, the curve is defined by R = 4sinθ + cosθ, with θ between 270° and 360°, where sine is negative or zero, and cosine is positive or zero.
How do you determine the area of the part of the circle in the fourth quadrant for R = 4sinθ + cosθ?
The area is calculated by integrating (1/2) R² with respect to θ over the θ interval corresponding to the fourth quadrant, typically from 270° to 360°.
What is the formula to find the area enclosed by a polar curve R = f(θ) in a specific interval?
The area A = (1/2) ∫ from θ₁ to θ₂ of [R(θ)]² dθ, where θ₁ and θ₂ define the interval of interest—in this case, the fourth quadrant.
How do you identify the bounds of integration for the fourth quadrant in this problem?
The bounds are θ = 270° (3π/2 radians) to θ = 360° (2π radians), capturing the entire fourth quadrant where the curve exists.
What steps are involved in computing the area of the part of the circle for R = 4sinθ + cosθ in the fourth quadrant?
First, express R² = (4sinθ + cosθ)², then integrate (1/2) R² over θ from 270° to 360°, simplifying the integral to find the area.
Does the function R = 4sinθ + cosθ produce a standard circle in the polar coordinate system?
Not exactly; it represents a sinusoidal curve that can form a circle or other conic sections depending on the coefficients, but in this case, it traces a limacon-like shape.
What is the significance of the coefficients 4 and 1 in the equation R = 4sinθ + cosθ?
They determine the shape and size of the curve; specifically, they influence the distance from the origin and the extent of the curve in different directions.
How can the symmetry of the curve help in calculating the area in the fourth quadrant?
If the curve is symmetric about an axis, you can calculate the area in one quadrant and then multiply accordingly; however, in this case, direct integration over the specific bounds is more precise.
What challenges might arise when computing the area for R = 4sinθ + cosθ in the fourth quadrant?
Challenges include simplifying R², dealing with the mixed sine and cosine terms, and accurately setting the limits of integration to cover only the fourth quadrant.
Can the area calculation be verified graphically for the curve R = 4sinθ + cosθ in the fourth quadrant?
Yes, plotting the curve in a polar graphing tool can provide a visual confirmation of the area, ensuring the accuracy of the integral bounds and the computed area.