2. The Profit When Selling 'X' Pairs Of Shoes Is Defined By The Function P(x)=-8x2 +80x-192. How Many

2. The Profit When Selling 'X' Pairs Of Shoes Is Defined By The Function P(x)=-8x2 +80x-192. How Many pairs of shoes should a seller aim to sell to maximize profit? Understanding the profit function and its implications is essential for any business owner or entrepreneur involved in selling shoes or similar products. In this article, we will analyze the quadratic profit function, interpret its key features, and determine the optimal number of units to sell for maximum profit.

Understanding the Profit Function P(x) = -8x² + 80x - 192

What Does the Function Represent?

The function P(x) = -8x² + 80x - 192 models the profit earned from selling x pairs of shoes. Here:
  • x represents the number of pairs sold.
  • P(x) indicates the profit associated with selling x pairs.
Since the quadratic coefficient is negative (-8), the parabola opens downward, meaning the function has a maximum point that indicates the maximum profit achievable.

Key Components of the Function

  • Quadratic Term (-8x²): Represents decreasing returns after a certain point, indicating that beyond some sales volume, profit begins to decline.
  • Linear Term (80x): Represents the initial increase in profit per additional pair sold.
  • Constant Term (-192): Represents fixed costs or baseline expenses that are incurred regardless of the number of shoes sold.

Finding the Number of Shoes to Maximize Profit

Vertex of the Parabola

The maximum profit occurs at the vertex of the parabola described by the quadratic function. The x-coordinate of the vertex can be found using the formula:

x = -b / (2a)

where:


  • a = -8

  • b = 80


Calculating:

x = -80 / (2 -8) = -80 / -16 = 5

Thus, selling 5 pairs of shoes maximizes profit.

Calculating the Maximum Profit

To find the maximum profit, substitute x = 5 back into the profit function:

P(5) = -8(5)² + 80(5) - 192
= -8(25) + 400 - 192
= -200 + 400 - 192
= 200 - 192
= 8

Therefore, the maximum profit that can be achieved is $8 when selling 5 pairs of shoes.

Interpreting the Results for Business Strategy

Implications of the Profit Function

  • Selling fewer than 5 pairs results in less profit.
  • Selling more than 5 pairs causes the profit to decrease due to the quadratic term dominating.
  • The small maximum profit of $8 suggests that, at least according to this model, the profit margins are quite slim for the given costs and revenues.

Practical Considerations

While the mathematical model indicates that selling exactly 5 pairs maximizes profit, real-world scenarios should consider:
  • Market demand fluctuations.
  • Cost variations.
  • Competition.
  • Marketing efforts.
It’s essential to use this analysis as a guide rather than an absolute rule.

Additional Insights and Applications

Understanding the Shape of the Profit Function

Since the parabola opens downward, the profit function is concave, meaning:
  • There is a clear maximum point.
  • Beyond the vertex, additional sales lead to decreasing profit.
This shape highlights the importance of identifying optimal sales levels.

Using the Function for Business Planning

  • Pricing Strategy: Adjust pricing to influence the profit function’s parameters.
  • Sales Targets: Set realistic sales targets aligned with profit maximization.
  • Cost Management: Explore ways to reduce fixed costs to shift the profit curve upward.

Conclusion: How Many Pairs of Shoes Should Be Sold?

Based on the quadratic profit function P(x) = -8x² + 80x - 192, the optimal number of pairs of shoes to sell is 5, which yields a maximum profit of $8. While this mathematical result provides a clear target, real-world factors should influence final business decisions. Understanding the profit function’s behavior enables entrepreneurs to optimize sales strategies, manage costs effectively, and make data-driven decisions to maximize profitability.

Summary of Key Points

    • The profit function is a downward-opening parabola, indicating a maximum point exists.
    • The maximum profit occurs at x = 5 pairs of shoes.
    • Maximum profit at this point is $8.
    • Mathematical analysis guides business decisions, but real-world factors must also be considered.
    • Understanding quadratic functions helps in strategic planning and maximizing profits.

By applying the principles of quadratic functions and profit analysis, business owners can make informed decisions that optimize sales and profitability, ensuring sustained success in competitive markets.

Frequently Asked Questions

What is the profit function when selling 'x' pairs of shoes?
The profit function is P(x) = -8x^2 + 80x - 192.
How do you find the number of pairs of shoes that maximizes profit?
To maximize profit, find the vertex of the parabola represented by P(x). For P(x) = -8x^2 + 80x - 192, the x-coordinate of the vertex is -b/(2a).
What is the value of 'x' that gives the maximum profit?
The maximum profit occurs at x = -80 / (2 -8) = 5 pairs of shoes.
What is the maximum profit when selling the optimal number of shoes?
Substitute x=5 into P(x): P(5) = -8(25) + 80(5) - 192 = -200 + 400 - 192 = 8. So, the maximum profit is $8.
How many pairs of shoes should be sold to break even?
Set P(x) = 0 and solve for x: -8x^2 + 80x - 192 = 0.
What are the break-even points for the number of shoes sold?
Solve the quadratic: -8x^2 + 80x - 192 = 0. Dividing both sides by -8 gives x^2 - 10x + 24 = 0. Using quadratic formula: x = [10 ± √(100 - 96)] / 2 = [10 ± √4]/2.
What are the two break-even points?
x = [10 + 2]/2 = 6 and x = [10 - 2]/2 = 4. So, selling 4 or 6 pairs of shoes results in zero profit.
Is the profit function a parabola opening upwards or downwards?
Since the coefficient of x^2 is negative (-8), the parabola opens downward.
What does the vertex of the parabola represent in this context?
The vertex represents the number of shoes to be sold to achieve maximum profit, which is at x = 5 pairs.
How can this profit function be used to inform sales strategies?
By understanding the optimal number of pairs to sell (x=5), businesses can maximize profits, and knowing the break-even points helps set realistic sales targets.