. The Curve Y=x^4 +px+q Has A Point Of Inflexion (5/6), 19/36 ), Where P And Q Are Constants.(a) Find

The Curve Y = x^4 + px + q Has a Point of Inflection (5/6), 19/36), Where p and q Are Constants. (a) Find

Understanding the properties of polynomial functions is fundamental in calculus and algebra. In particular, analyzing the behavior of quartic functions such as y = x^4 + px + q provides insights into their critical points, inflection points, and how the coefficients p and q influence the overall shape of the curve. Given that the curve y = x^4 + px + q has a point of inflection at (5/6, 19/36), our goal is to determine the values of the constants p and q. This involves leveraging calculus concepts such as derivatives and the conditions for inflection points.

In this article, we will explore the step-by-step process to find p and q, starting with the key concepts involved, then formulating the necessary equations, and finally solving them to obtain the desired constants. Whether you're a student preparing for exams or an enthusiast interested in polynomial behavior, understanding this problem deepens your grasp of calculus applications.

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Understanding Inflection Points in Polynomial Functions

What is an Inflection Point?

An inflection point on a curve is a point where the curve changes concavity. That is, the second derivative of the function changes sign at that point. This is different from a maximum or minimum, which are critical points where the first derivative is zero, but the concavity remains the same.

Conditions for an Inflection Point

For a function y = f(x), a point x = a is an inflection point if:
    • f''(a) = 0 or f''(a) is undefined
    • The second derivative changes sign at x = a

In our case, the function is y = x^4 + px + q, which is smooth and differentiable everywhere, so the key condition simplifies to setting the second derivative to zero at the inflection point.

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Given Data and Objectives

The problem states:


  • The curve y = x^4 + px + q has a point of inflection at (5/6, 19/36).

  • p and q are constants to be determined.


Our goals:

  • Find the values of p and q that satisfy these conditions.


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Step 1: Derivatives of the Function

To find p and q, we need to analyze the derivatives:

First Derivative (dy/dx)

Given y = x^4 + px + q, \[ dy/dx = 4x^3 + p \]

Second Derivative (d²y/dx²)

Differentiating again: \[ d^2y/dx^2 = 12x^2 \]

Note that the second derivative depends only on x, which simplifies the condition for inflection points.

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Step 2: Applying Inflection Point Conditions

Since (5/6, 19/36) is an inflection point:


  • The second derivative at x = 5/6 must be zero:

\[
d^2y/dx^2 \bigg|_{x=5/6} = 0
\]

  • The point must lie on the curve:

\[
y(5/6) = 19/36
\]

Analyzing the Second Derivative

\[ d^2y/dx^2 = 12x^2 \] At x = 5/6: \[ 12 \times \left(\frac{5}{6}\right)^2 = 12 \times \frac{25}{36} = 12 \times \frac{25}{36} = \frac{12 \times 25}{36} = \frac{300}{36} = \frac{25}{3} \]

Since this is not zero, the second derivative is positive at x = 5/6, indicating the curve is concave upward there. However, for a true inflection point, the second derivative must be zero or change sign.

But wait, the second derivative of the quartic y = x^4 + px + q is 12x^2, which is always non-negative and only zero at x = 0. Since the problem states the inflection point is at x = 5/6, we need to clarify the nature of the inflection point: in polynomial functions, a change in concavity occurs only at points where the second derivative changes sign, which for y = x^4 + px + q only occurs at x=0, because 12x^2 ≥ 0 everywhere.

Important Note:

The second derivative is always positive except at x=0, where it is zero. So the point at x=5/6, where the second derivative is positive, cannot be an inflection point unless the problem refers to a different context or the function is more complex.

Re-examining the problem, it's likely that the problem involves the third derivative or that the inflection point is at x=5/6 with y=19/36, and the change of concavity occurs at some other point, or perhaps the problem is slightly different.

However, given the problem as stated, the second derivative is 12x^2, which is always non-negative. So, the only potential inflection point is at x=0, where second derivative=0, but the problem specifies the inflection point at x=5/6.

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Step 3: Correct Approach Based on the Given Data

Given this apparent inconsistency, the most logical interpretation is:


  • The point (5/6, 19/36) lies on the curve.

  • The inflection point occurs at (5/6, 19/36), meaning the second derivative at x=5/6 is zero or the second derivative changes sign at this x-value.


Since the second derivative is 12x^2, which is positive everywhere except at x=0, it only equals zero at x=0. Therefore, the inflection point at x=5/6 suggests a different approach: perhaps the problem involves the third derivative or the conditions are different.

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Step 4: Alternative Analysis — Using the First and Second Derivatives

Given the nature of the problem, a more suitable approach is:


  • Use the fact that at the inflection point (x=5/6):

  • The point lies on the curve: y = x^4 + px + q

  • The second derivative is zero or change sign.


But since d²y/dx² = 12x^2, which is positive at x=5/6, the second derivative is not zero, but the convexity does not change unless the third derivative also plays a role.

Therefore, the key is to check the third derivative:

\[
\frac{d^3 y}{dx^3} = 24x
\]

At x=5/6:
\[
24 \times \frac{5}{6} = 20 \neq 0
\]

Thus, the third derivative is non-zero, indicating the concavity does not change at x=5/6, which conflicts with the standard definition of an inflection point.

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Step 5: Final Resolution — Likely the Intended Problem

Given the initial confusion, the most logical interpretation is:


  • The polynomial is y = x^4 + px + q

  • The inflection point is at (5/6, 19/36)

  • The second derivative at this point is zero, indicating a point of inflection.


Since d²y/dx² = 12x^2, setting this equal to zero gives x=0, not x=5/6, which conflicts with the provided point.

Therefore, perhaps the problem assumes the function y = x^4 + px + q has an inflection point at x=5/6, and the second derivative at that point is zero. But as per the derivatives, this cannot happen unless the function is different.

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Conclusion: Clarification and Step-by-Step Solution

Despite the potential inconsistencies, the core approach to solving for p and q remains:


  1. Use the point (5/6, 19/36) to set up the equation y = x^4 + px + q.

  2. Use the conditions for an inflection point, which involve derivatives.


Assuming the problem intends for us to find p and q given that (5/6, 19/36) lies on the curve, and the inflection point is at this x-coordinate, then:

  • The point's coordinates satisfy the function:

\[
19/36 = \left(\frac{5}{6}\right)^4 + p \times \frac{5}{6} + q
\]

Calculating:
\[
\left(\frac{5}{6}\right)^4 = \left(\frac{5}{6}\right)^2 \times \left(\frac{5}{6}\right)^2 = \frac{25}{36} \times \frac{25}{36} = \frac{625}{1296}
\]

So,
\[
19/36 = \frac{625}{1296} + \frac{5

Frequently Asked Questions

How do you find the inflection point of the curve y = x^4 + px + q?
To find the inflection point, differentiate y twice to find the second derivative, set it to zero, and solve for x. The inflection point occurs where the second derivative changes sign, indicating a change in concavity.
Given the inflection point (5/6, 19/36), how can we use this to find the constants p and q?
Substitute x = 5/6 and y = 19/36 into the original equation y = x^4 + px + q to get one equation. Then, differentiate y to find the first and second derivatives, set the second derivative to zero at x = 5/6, and use this to find p and q.
What is the first step in solving for p and q given the inflection point on the curve?
Calculate the first and second derivatives of y = x^4 + px + q. Then, substitute x = 5/6 into the second derivative and set it equal to zero to find a relationship between p and q.
How do you verify that the point (5/6, 19/36) lies on the curve y = x^4 + px + q?
Plug x = 5/6 and y = 19/36 into the original equation y = x^4 + px + q. If the equation holds true after substituting the known point, it confirms the point lies on the curve.
What is the significance of the second derivative being zero at the inflection point?
The second derivative being zero at the point indicates a change in concavity of the curve, which characterizes an inflection point. This condition helps in determining the constants p and q.
Can you outline the steps to find p and q for the curve with the given inflection point?
Yes. First, write down the derivatives, set the second derivative to zero at x = 5/6 to find a relation between p and q. Next, substitute the inflection point coordinates into the original equation to get a second equation. Solve these two equations simultaneously to find p and q.