A Is An Arithmetic Sequence Where The 1st Term Of The Sequence Is -2 And The 15th Term Of The Sequence

A Is An Arithmetic Sequence Where The 1st Term Of The Sequence Is -2 And The 15th Term Of The Sequence

In mathematics, sequences are fundamental constructs that help us understand patterns, progressions, and relationships between numbers. Among the various types of sequences, an arithmetic sequence stands out due to its simplicity and wide application across different fields such as finance, physics, and computer science. Specifically, when analyzing an arithmetic sequence where the first term is known, and a particular term—like the 15th—is specified, it becomes a powerful exercise in understanding how common differences shape the overall sequence. This article delves into the concept of an arithmetic sequence with a first term of -2 and explores how to determine the 15th term, as well as related properties such as the common difference, general term formula, sum of the sequence, and real-world applications.

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Understanding Arithmetic Sequences

Definition of Arithmetic Sequence

An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms remains constant. This constant difference is called the common difference (denoted as \(d\)). The sequence progresses by adding (or subtracting) this common difference to each term to obtain the next term.

Mathematically, an arithmetic sequence is represented as:

\[
a, a + d, a + 2d, a + 3d, \ldots
\]

where:


  • \(a\) is the first term of the sequence,

  • \(d\) is the common difference.


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Key Properties of Arithmetic Sequences

  • Constant Difference: The difference between any two successive terms is always \(d\).
  • General Term (Explicit Formula): The \(n^{th}\) term can be expressed as:
\[ a_n = a + (n - 1)d \]
  • Sum of First \(n\) Terms: The sum of the first \(n\) terms, \(S_n\), can be calculated using:
\[ S_n = \frac{n}{2} \left( 2a + (n - 1)d \right) \]

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Given Data and Objective

From the problem statement, we know:


  • The first term of the sequence: \( a_1 = -2 \)

  • The 15th term of the sequence: \( a_{15} = ? \)


Our goal is to determine:

  • The value of the 15th term \(a_{15}\),

  • The common difference \(d\),

  • The general term formula for the sequence,

  • The sum of the first 15 terms,

  • And discuss the implications and applications of such sequences.


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Determining the Common Difference

Using the Formula for the \(n^{th}\) Term

Recall the explicit formula for the \(n^{th}\) term of an arithmetic sequence:

\[
a_n = a + (n - 1)d
\]

Applying this to the 15th term:

\[
a{15} = a1 + (15 - 1)d = -2 + 14d
\]

However, since the problem does not specify the value of \(a_{15}\), it implies that the 15th term is either to be calculated once the common difference is known or to be expressed in terms of \(d\).

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Assuming the 15th Term is Known

If, for example, the 15th term is given as a specific value, say \(a_{15} = x\), then:

\[
x = -2 + 14d
\]

From this, the common difference \(d\) can be calculated as:

\[
d = \frac{x + 2}{14}
\]

Example Calculation:

Suppose the 15th term is 10, then:

\[
10 = -2 + 14d
\]
\[
14d = 12
\]
\[
d = \frac{12}{14} = \frac{6}{7}
\]

Thus, the common difference is \(\frac{6}{7}\).

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Expressing the Sequence and Calculating Specific Terms

General Term Formula

With \(a = -2\) and \(d\) known, the explicit formula for the \(n^{th}\) term becomes:

\[
a_n = -2 + (n - 1)d
\]

Example:

Using the previous \(d = \frac{6}{7}\), the explicit formula is:

\[
a_n = -2 + (n - 1) \times \frac{6}{7}
\]

This allows us to find any term in the sequence, such as:


  • The 16th term:


\[
a_{16} = -2 + 15 \times \frac{6}{7} = -2 + \frac{90}{7} = -2 + 12.857 \approx 10.857
\]

  • The 20th term:


\[
a_{20} = -2 + 19 \times \frac{6}{7} = -2 + \frac{114}{7} \approx -2 + 16.286 \approx 14.286
\]

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Sum of the First 15 Terms

Using the Sum Formula

The sum of the first \(n\) terms is given by:

\[
S_n = \frac{n}{2} \left( 2a + (n - 1)d \right)
\]

Applying this to the first 15 terms:

\[
S_{15} = \frac{15}{2} \left( 2 \times -2 + (15 - 1)d \right)
\]

Simplify:

\[
S_{15} = \frac{15}{2} \left( -4 + 14d \right)
\]

Using the earlier example where \(d = \frac{6}{7}\):

\[
S_{15} = \frac{15}{2} \left( -4 + 14 \times \frac{6}{7} \right) = \frac{15}{2} \left( -4 + 12 \right) = \frac{15}{2} \times 8 = 15 \times 4 = 60
\]

Hence, the sum of the first 15 terms in this specific case is 60.

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Real-World Applications of Arithmetic Sequences

Financial Planning

Arithmetic sequences are relevant when modeling situations involving regular, fixed increases or decreases, such as:


  • Loan repayments, where a fixed amount is paid periodically.

  • Savings plans, where a fixed amount is deposited at regular intervals.

  • Depreciation of assets, where value decreases by a constant amount over time.


Physics and Engineering

Sequences with constant differences model:


  • Uniform acceleration scenarios.

  • Equally spaced measurements or signals.


Computer Science



  • Iterative algorithms with linear progression.

  • Memory allocation patterns with fixed step sizes.


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Advanced Topics and Variations

Arithmetic Progressions with Negative or Zero Common Difference

  • Negative difference: sequence decreases over time, e.g., depreciation.
  • Zero difference: sequence consists of constant terms.

Arithmetic Sequence vs. Geometric Sequence

While arithmetic sequences involve adding a fixed number, geometric sequences involve multiplying by a fixed ratio.

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Summary and Key Takeaways

  • An arithmetic sequence is characterized by a constant difference between terms.
  • Given the first term \(a_1 = -2\), the sequence's general term depends on the common difference \(d\).
  • To find the 15th term, knowledge of \(d\) or the 15th term value is essential.
  • The explicit formula for the \(n^{th}\) term is:
\[ an = a1 + (n - 1)d \]
  • The sum of the first \(n\) terms:
\[ Sn = \frac{n}{2} \left( 2a1 + (n - 1)d \right) \]
  • Arithmetic sequences find applications across finance, physics, engineering, and computer science.
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Conclusion

Understanding arithmetic sequences where the first term is known and a specific term, such as the 15th, can be calculated forms the foundation for more advanced studies in sequences and series. By mastering the explicit formulas and sum calculations, students and professionals can analyze linear progressions effectively. Whether modeling financial growth, decay, or physical phenomena, arithmetic sequences serve as a versatile and essential mathematical tool.

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Note: To fully specify the sequence and compute precise values, the actual 15th term's value or the common difference must be known. Once either is provided, all other properties follow straightforwardly from the formulas discussed.

Frequently Asked Questions

What is the common difference in an arithmetic sequence where the first term is -2 and the 15th term is 10?
The common difference is 1. To find it, use the formula for the nth term: a_n = a_1 + (n - 1)d. Given a_1 = -2 and a_15 = 10, substitute: 10 = -2 + (15 - 1)d → 10 = -2 + 14d → 14d = 12 → d = 12/14 = 6/7.
How do you find the 15th term of an arithmetic sequence if the first term is -2 and the common difference is known?
Use the formula a_n = a_1 + (n - 1)d. For the 15th term, plug in n=15: a_{15} = -2 + (15 - 1)d = -2 + 14d.
If the first term of an arithmetic sequence is -2 and the 15th term is 10, what is the value of the 10th term?
First, find the common difference: d = (10 - (-2)) / (15 - 1) = 12 / 14 = 6/7. Then, the 10th term is a_{10} = -2 + (10 - 1)(6/7) = -2 + 9 (6/7) = -2 + (54/7) = (-14/7) + (54/7) = 40/7 ≈ 5.714.
Can you determine the general formula for the nth term of this arithmetic sequence?
Yes. Since the first term a_1 = -2 and the common difference d = 6/7, the nth term is a_n = -2 + (n - 1)(6/7).
What is the significance of the 15th term in understanding the sequence?
The 15th term helps determine the common difference and the general pattern of the sequence, allowing you to find any other term and understand the sequence's behavior.