Question 3: Derive The Expression Of Input Impedance As Seen By The Primary Side Of The Linked Coil As

Question 3: Derive The Expression Of Input Impedance As Seen By The Primary Side Of The Linked Coil As

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Introduction

In electrical engineering, particularly in the analysis of coupled inductors or transformers, understanding the input impedance as seen from the primary side is fundamental. It influences how signals are transferred, how power is delivered, and how the system interacts with external circuits. The primary side impedance, when viewed through the lens of the coupled coil, depends on various parameters such as the inductances of the coils, the mutual inductance, and the load connected to the secondary coil.

This article will provide an in-depth derivation of the expression for the input impedance as seen from the primary side of a linked coil (transformer). We will systematically analyze the coupled circuit, introduce relevant parameters, and step through the mathematical derivation, culminating in the general impedance formula. Such understanding is essential for designing efficient transformers, analyzing coupled inductors, and optimizing circuit performance.

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Basics of Mutual Induction and Coupled Coils

Before diving into the derivation, let’s review some fundamental concepts:

Self-Inductance

  • The self-inductance \(L\) of a coil is the property that opposes changes in current flowing through it.
  • It is measured in henrys (H) and relates the coil's magnetic field to the current.

Mutual Inductance

  • When two coils are placed close to each other, a change in current in one coil induces an emf in the other.
  • This phenomenon is characterized by the mutual inductance \(M\), also measured in henrys.
  • The mutual inductance depends on the coil geometry, the core material, and the relative positioning of the coils.

Transformer Analogy

  • A typical transformer consists of a primary coil (input side) and a secondary coil (output side).
  • The coils are magnetically linked, allowing energy transfer via magnetic flux.
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Modeling The Coupled Coils

Consider a transformer with the following parameters:

    • Primary coil with inductance \(L_1\)
    • Secondary coil with inductance \(L_2\)
    • Mutual inductance \(M\)
    • Load connected across secondary with impedance \(Z_L\)

The circuit can be modeled as two inductors coupled through mutual inductance, with the secondary connected to a load.

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Mathematical Representation of the Circuit

The voltages and currents in the primary and secondary coils are related as:

\[
\begin{cases}
V1 = j \omega L1 I1 + j \omega M I2 \\
V2 = j \omega M I1 + j \omega L2 I2
\end{cases}
\]

where:


  • \(V1\) and \(V2\) are the voltages across primary and secondary, respectively.

  • \(I1\) and \(I2\) are the currents in the primary and secondary.

  • \(j\) is the imaginary unit, and \(\omega\) is the angular frequency.


Assuming sinusoidal steady-state operation, the impedance relationships can be written as:

\[
V1 = Z{in} I_1
\]

Our goal is to determine \(Z_{in}\), the input impedance as seen from the primary.

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Deriving The Input Impedance

Let's proceed step-by-step to derive the expression:

Step 1: Express Secondary Current \(I_2\)

The secondary is connected to a load \(Z_L\), so:

\[
V2 = ZL I_2
\]

Using the second circuit equation:

\[
V2 = j \omega M I1 + j \omega L2 I2
\]

Substitute \(V2 = ZL I_2\):

\[
ZL I2 = j \omega M I1 + j \omega L2 I_2
\]

Rearranged to solve for \(I_2\):

\[
(ZL - j \omega L2) I2 = j \omega M I1
\]

\[
I2 = \frac{j \omega M I1}{ZL - j \omega L2}
\]

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Step 2: Express Primary Voltage \(V1\) in Terms of \(I1\)

From the first equation:

\[
V1 = j \omega L1 I1 + j \omega M I2
\]

Substitute the expression for \(I_2\):

\[
V1 = j \omega L1 I1 + j \omega M \times \frac{j \omega M I1}{ZL - j \omega L2}
\]

Note that:

\[
j \omega M \times j \omega M = (j)^2 (\omega)^2 M^2 = - (\omega)^2 M^2
\]

Therefore:

\[
V1 = j \omega L1 I1 - \frac{(\omega)^2 M^2 I1}{ZL - j \omega L2}
\]

Factor out \(I_1\):

\[
V1 = I1 \left[ j \omega L1 - \frac{\omega^2 M^2}{ZL - j \omega L_2} \right]
\]

So, the input impedance \(Z_{in}\) as seen from the primary is:

\[
Z{in} = \frac{V1}{I1} = j \omega L1 - \frac{\omega^2 M^2}{ZL - j \omega L2}
\]

This is the general expression for the input impedance of a coupled coil with load \(Z_L\) connected to the secondary.

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Final Expression of Input Impedance

The derived formula:

\[
\boxed{
Z{in} = j \omega L1 - \frac{\omega^2 M^2}{ZL - j \omega L2}
}
\]

encapsulates how the primary impedance is influenced by the secondary load, the mutual inductance, and the inductances of both coils.

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Special Cases and Interpretations

Understanding the behavior of the impedance expression under specific conditions is vital:

1. Open-Circuited Secondary (\(Z_L \to \infty\))

  • When the secondary is open, no current flows (\(I_2 \to 0\)), so:
\[ Z{in} = j \omega L1 \]
  • The primary sees only its self-inductance.

2. Short-Circuited Secondary (\(Z_L = 0\))

  • When secondary is shorted:
\[ Z{in} = j \omega L1 - \frac{\omega^2 M^2}{- j \omega L2} = j \omega L1 + \frac{\omega^2 M^2}{j \omega L_2} \]

Simplify:

\[
Z{in} = j \omega L1 + \frac{\omega M^2}{L_2}
\]


  • The primary impedance is increased by the mutual coupling.


3. Matched Load (\(ZL = j \omega L2\))



  • When load impedance matches the secondary inductance's impedance:


\[
Z{in} = j \omega L1 - \frac{\omega^2 M^2}{j \omega L2 - j \omega L2} \rightarrow \text{Indeterminate}
\]

  • Special care is required here, but generally, this indicates resonance or specific coupling conditions.


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Implications for Transformer Design and Analysis

The derived expression guides engineers in predicting how the primary impedance varies with load and coupling:


  • Designing for Efficiency: Knowing \(Z_{in}\) helps match the source impedance for maximum power transfer.

  • Tuning Resonance: Adjusting inductances or coupling affects the resonant conditions.

  • Leakage and Coupling Coefficient: The mutual inductance \(M\) relates to the coupling coefficient \(k\):


\[
M = k \sqrt{L1 L2}
\]

which influences the impedance transformation ratio.

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Conclusion

In this comprehensive analysis, we derived the expression for the input impedance as seen from the primary side of a linked coil or transformer:

\[
\boxed{
Z{in} = j \omega L1 - \frac{\omega^2 M^2}{ZL - j \omega L2}
}
\]

This formula encapsulates the effects of mutual inductance, secondary load, and coil inductances, providing crucial insights for transformer design, circuit analysis, and electromagnetic compatibility considerations. Understanding how to manipulate and interpret this impedance aids engineers in optimizing performance, achieving desired transfer characteristics, and ensuring system stability.

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Frequently Asked Questions

How is the input impedance seen from the primary side of a linked coil derived in a transformer?
The input impedance is derived by referring the secondary impedance to the primary side using the square of the turns ratio. It involves expressing the secondary impedance in terms of primary parameters and applying the impedance transformation formula Z_in = (N1/N2)^2 Z_secondary.
What is the significance of the turns ratio in calculating the primary input impedance of a linked coil?
The turns ratio (N1/N2) determines how the secondary impedance appears on the primary side. It allows us to transform the secondary impedance to an equivalent primary impedance, which is essential for accurately analyzing the circuit from the primary perspective.
Can you provide the general formula for the input impedance as seen from the primary side of a transformer with a linked coil?
Yes. The general formula is Z_in = (N1/N2)^2 Z_secondary, where Z_secondary is the impedance connected across the secondary coil, and N1 and N2 are the number of turns on the primary and secondary coils, respectively.
How does leakage impedance affect the derivation of input impedance on the primary side of a linked coil?
Leakage impedance adds to the ideal transformed impedance, increasing the total input impedance seen from the primary side. It must be included in the secondary impedance before transforming it to the primary side to accurately derive the total input impedance.
What assumptions are typically made when deriving the input impedance of a linked coil as seen from the primary side?
Common assumptions include neglecting core losses, assuming ideal coupling (no leakage flux), and considering the transformer to be linear and lossless. These simplify the derivation to mainly involve the turns ratio and secondary impedance transformation.