The Molar Solubility Of CuI Is 2.26 10 -6 M In Pure Water. Calculate The K Sp For CuI.5.11 10-12 M4.62

The Molar Solubility Of CuI Is 2.26 10 -6 M In Pure Water. Calculate The K Sp For CuI. 5.11 10-12 M 4.62

Understanding the solubility of ionic compounds like copper(I) iodide (CuI) is fundamental in chemistry, especially when analyzing equilibrium processes in aqueous solutions. In this article, we will explore how to determine the solubility product constant (Ksp) of CuI based on given molar solubility data. We will also delve into the concepts of solubility, equilibrium, and how to interpret experimental measurements to calculate Ksp accurately.

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Overview of CuI and Its Solubility

Copper(I) iodide (CuI) is an insoluble salt that dissociates in water according to the following equilibrium:

\[ \text{CuI (s)} \leftrightarrow \text{Cu}^+ (aq) + \text{I}^- (aq) \]

The extent to which CuI dissolves in water is quantified by its molar solubility, which is the molar concentration of CuI that dissolves to reach equilibrium. The solubility product constant (Ksp) expresses the equilibrium concentrations of the ions in solution.

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Understanding Molar Solubility and Ksp

What Is Molar Solubility?

  • Molar solubility refers to the number of moles of a solute that dissolve per liter of solution to form a saturated solution.
  • For CuI, molar solubility (denoted as \( s \)) is the molarity of CuI in a saturated solution.

What Is Ksp?

  • The solubility product constant, Ksp, is an equilibrium expression that relates the concentrations of ions in a saturated solution.
  • For CuI, the Ksp expression is:
\[ K_{sp} = [\text{Cu}^+][\text{I}^-] \]
  • Since CuI dissociates into one Cu\(^+\) and one I\(^-\) ion, their concentrations are equal at equilibrium, both equal to the molar solubility \( s \).
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Calculating Ksp from Molar Solubility

Given the molar solubility \( s = 2.26 \times 10^{-6} \, M \), the calculation of Ksp is straightforward:

\[ K_{sp} = s \times s = s^2 \]

\[ K_{sp} = (2.26 \times 10^{-6})^2 \]

\[ K_{sp} = 5.11 \times 10^{-12} \]

This matches the given value of approximately \( 5.11 \times 10^{-12} \), confirming the consistency of the data.

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Interpreting the Data and Additional Values

The mention of "4.62" in the original prompt appears to be a fragment or an incomplete reference. It might relate to another measurement or a different calculation, but based on the context, the primary focus is on calculating Ksp from molar solubility.

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Additional Calculations and Context

Comparing Experimental Values

  • Experimental determination of Ksp provides insight into how soluble CuI is in pure water.
  • The low value indicates that CuI is very insoluble, consistent with its role as a precipitate in analytical chemistry.

Estimating Solubility in Other Conditions

  • Factors such as temperature, presence of complexing agents, or ionic strength can influence solubility.
  • For example, in the presence of complexing agents, the effective solubility may increase, affecting the Ksp indirectly.
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Practical Applications of Ksp and Molar Solubility

Understanding and calculating Ksp has various practical implications:


  • Precipitation Reactions: Determining conditions to precipitate or dissolve salts.

  • Environmental Chemistry: Predicting mineral solubility in natural waters.

  • Pharmaceuticals: Controlling solubility for drug formulation.

  • Analytical Chemistry: Quantitative analysis based on solubility equilibria.


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Step-by-Step Summary for Calculating Ksp

  1. Identify the molar solubility \( s \): Given as \( 2.26 \times 10^{-6} \, M \).
  2. Write the dissociation equation: \( \text{CuI (s)} \leftrightarrow \text{Cu}^+ (aq) + \text{I}^- (aq) \).
  3. Express ion concentrations at equilibrium: Both are equal to \( s \).
  4. Calculate Ksp: \( K_{sp} = s^2 \).
  5. Compute the value: \( (2.26 \times 10^{-6})^2 = 5.11 \times 10^{-12} \).
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Conclusion

In summary, the molar solubility of CuI in pure water is \( 2.26 \times 10^{-6} \, M \). Using this value, the solubility product constant (Ksp) can be calculated as:

\[ \boxed{K_{sp} = 5.11 \times 10^{-12}} \]

This extremely low Ksp value underscores the insolubility of CuI, aligning with its common use as a precipitate in various chemical processes. Accurate knowledge of solubility and Ksp is vital for predicting the behavior of ionic compounds in aqueous solutions, whether in laboratory settings, environmental studies, or industrial applications.

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Additional Reading and Resources

  • "Chemistry: The Central Science" by Brown, LeMay, Bursten, and Murphy
  • Online calculators for solubility product computations
  • Research articles on copper halide solubility and complex formation
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Keywords: CuI solubility, molar solubility, Ksp calculation, ionic equilibrium, insoluble salts, solubility product constant, aqueous chemistry

Frequently Asked Questions

What is the molar solubility of CuI in pure water?
The molar solubility of CuI in pure water is 2.26 × 10⁻⁶ M.
How is the solubility product constant (Ksp) related to molar solubility?
Ksp is calculated using the concentrations of ions in saturated solution; for CuI, Ksp = [Cu⁺][I⁻], which depends on the molar solubility.
What is the formula to calculate Ksp for CuI given its molar solubility?
Ksp = (molar solubility)², because CuI dissociates into Cu⁺ and I⁻ ions in a 1:1 ratio.
What is the value of Ksp for CuI based on its molar solubility?
Ksp = (2.26 × 10⁻⁶)² = 5.11 × 10⁻¹².
How does the molar solubility of CuI relate to its solubility product constant?
The molar solubility directly influences Ksp; higher solubility results in a larger Ksp, indicating greater solubility.
Why is the square of molar solubility used in calculating Ksp for CuI?
Because CuI dissociates into two ions in a 1:1 ratio, so Ksp = [Cu⁺][I⁻] = (molar solubility)².
What are the units of Ksp for CuI?
The units of Ksp are typically expressed as M² (molar squared), since it involves the product of ion concentrations.
Could the given value 4.62 relate to the calculation of Ksp?
No, based on the data, the correct Ksp is 5.11 × 10⁻¹²; 4.62 may be a distractor or unrelated value in this context.
What is the significance of knowing the Ksp of CuI?
Knowing the Ksp helps determine the solubility of CuI in water and predict whether it will precipitate under certain conditions.