Three Point Charges Of Q, = 6uC, Q2 =2uc, Q3= -4C Are Located At (0, 0), (3,0), And (3,3) Respectively.

Three Point Charges Of Q, = 6uC, Q2 =2uc, Q3= -4C Are Located At (0, 0), (3,0), And (3,3) Respectively.
This configuration of point charges presents an interesting scenario in electrostatics, illustrating fundamental principles such as Coulomb’s law, electric field calculation, and potential energy. Understanding the interactions among these charges is essential for grasping how electric forces operate in multi-charge systems. In this article, we will explore the detailed analysis of these three charges, including calculating the electric forces between them, determining the net electric field at various points, and evaluating the potential energy stored within this system.

Introduction to Point Charges and Coulomb’s Law

Before delving into the specific problem, it is important to review some foundational concepts in electrostatics.

What are Point Charges?

Point charges are idealized charges that have negligible size but possess a certain electric charge. They serve as simplified models to analyze electric interactions without considering the effects of charge distribution or physical dimensions. These charges exert forces on each other according to Coulomb’s law, which is fundamental in electrostatics.

Coulomb’s Law

Coulomb’s law states that the magnitude of the electrostatic force \( F \) between two point charges \( q1 \) and \( q2 \) separated by a distance \( r \) is given by:

\[
F = ke \frac{|q1 q_2|}{r^2}
\]

where:


  • \( F \) is the magnitude of the force (in newtons),

  • \( k_e \) is Coulomb’s constant (\( 8.9875 \times 10^9 \, \mathrm{Nm^2/C^2} \)),

  • \( q1 \) and \( q2 \) are the magnitudes of the charges (in coulombs),

  • \( r \) is the distance between the charges (in meters).


The direction of the force depends on the signs of the charges: like charges repel, opposite charges attract.

System Description and Coordinates

Given the charges and their positions, we can visualize the system as follows:

| Charge | Magnitude | Coordinates (x, y) | Sign |
|----------|--------------|----------------------|-------|
| \( Q_1 \) | 6 μC | (0, 0) | Positive |
| \( Q_2 \) | 2 μC | (3, 0) | Positive |
| \( Q_3 \) | -4 μC | (3, 3) | Negative |

Note: The charges are given in microcoulombs (μC) and coulombs (C). To maintain consistency, convert all charges to coulombs:


  • \( Q_1 = 6 \times 10^{-6} \, \mathrm{C} \)

  • \( Q_2 = 2 \times 10^{-6} \, \mathrm{C} \)

  • \( Q_3 = -4 \times 10^{-6} \, \mathrm{C} \)


This coordinate setup allows us to analyze the forces and fields systematically.

Calculating Electric Forces Between Charges

The first step in understanding the system is to compute the forces acting between each pair of charges.

Force Between \( Q1 \) and \( Q2 \)

  • Distance \( r_{12} \): The two charges are located at (0,0) and (3,0), so
\[ r_{12} = 3 \, \mathrm{m} \]
  • Magnitudes: \( |Q1| = 6 \times 10^{-6} \, \mathrm{C} \), \( |Q2| = 2 \times 10^{-6} \, \mathrm{C} \)
  • Applying Coulomb’s law:
\[ F{12} = ke \frac{|Q1 Q2|}{r_{12}^2} = (8.9875 \times 10^9) \times \frac{(6 \times 10^{-6})(2 \times 10^{-6})}{3^2} \] \[ F_{12} \approx 8.9875 \times 10^9 \times \frac{12 \times 10^{-12}}{9} \approx 8.9875 \times 10^9 \times 1.333 \times 10^{-12} \approx 0.012 \, \mathrm{N} \]

Since both are positive, they repel each other along the x-axis, with \( Q1 \) experiencing a force to the right and \( Q2 \) to the left.

Force Between \( Q1 \) and \( Q3 \)

  • Distance \( r_{13} \): Between (0,0) and (3,3),
\[ r_{13} = \sqrt{(3-0)^2 + (3-0)^2} = \sqrt{9 + 9} = \sqrt{18} \approx 4.24 \, \mathrm{m} \]
  • Coulomb force:
\[ F{13} = ke \frac{|Q1 Q3|}{r_{13}^2} = 8.9875 \times 10^9 \times \frac{(6 \times 10^{-6})(4 \times 10^{-6})}{(4.24)^2} \] \[ F_{13} \approx 8.9875 \times 10^9 \times \frac{24 \times 10^{-12}}{18} \approx 8.9875 \times 10^9 \times 1.333 \times 10^{-12} \approx 0.012 \, \mathrm{N} \]

Because \( Q3 \) is negative and \( Q1 \) is positive, they attract each other. The force on \( Q1 \) points toward \( Q3 \).

Force Between \( Q2 \) and \( Q3 \)

  • Distance \( r_{23} \): Between (3,0) and (3,3),
\[ r_{23} = 3 \, \mathrm{m} \]
  • Coulomb force:
\[ F_{23} = 8.9875 \times 10^9 \times \frac{(2 \times 10^{-6})(4 \times 10^{-6})}{3^2} \approx 8.9875 \times 10^9 \times \frac{8 \times 10^{-12}}{9} \approx 8.9875 \times 10^9 \times 0.888 \times 10^{-12} \approx 0.008 \, \mathrm{N} \]

Since \( Q2 \) is positive and \( Q3 \) negative, they attract each other, with the force on \( Q2 \) directed toward \( Q3 \).

Net Electric Field and Force on Each Charge

To understand how each charge experiences net forces, we need to calculate the electric field vectors at their locations.

Electric Field Due to a Single Charge

The electric field \( \vec{E} \) at a point due to a point charge \( q \) is:

\[
\vec{E} = k_e \frac{q}{r^2} \hat{r}
\]

where \( \hat{r} \) is the unit vector pointing from the charge to the point of interest.

Electric Field at \( Q_1 \)’s Position

  • Due to \( Q_2 \):
\[ \vec{E}{Q2} = ke \frac{Q2}{r{Q2}^2} \hat{r}{Q2} \]
  • Due to \( Q_3 \):
\[ \vec{E}{Q3} = ke \frac{Q3}{r{Q3}^2} \hat{r}{Q3} \]

Calculations involve vector addition of these fields to find the net electric field at \( Q1 \)’s position, which determines the force experienced by \( Q1 \).

Similarly, the electric fields at \( Q2 \) and \( Q3 \)’s positions can be calculated considering the contributions from the other charges.

Potential Energy of the System

The electrostatic potential energy \( U \) stored in a system of point charges is given by:

\[
U = \frac{1}{4\pi \varepsilon0} \left( \frac{Q1 Q2}{r{12}} + \frac{Q1 Q3}{r{13}} + \frac{Q2 Q3}{r{23}} \right)
\]

where \( \varepsilon_0 \)

Frequently Asked Questions

What is the net electric field at the origin (0,0) due to the three charges Q1, Q2, and Q3?
The net electric field at (0,0) is found by calculating the individual electric fields from each charge at that point and vectorially adding them. Q1 is at (0,0), so it creates an undefined field at its own location, typically considered as infinite or zero depending on context. Q2 at (3,0) produces a field pointing away from Q2 since it is positive, while Q3 at (3,3) produces a field pointing away from Q3 if positive or toward if negative. The combined field results from vector addition of these contributions.
How do the signs and magnitudes of the charges affect the direction of the electric field at a specific point?
The magnitude of each charge determines the strength of its electric field, while the sign indicates the direction: positive charges produce fields radiating outward, and negative charges produce fields directed inward. Therefore, at any point, the net electric field is the vector sum of all individual fields, with directions influenced by each charge's sign and position.
What is the potential energy of the system of three charges?
The total electrostatic potential energy of the system is given by the sum of potential energies between each pair of charges: U = k(Q1Q2/r12 + Q1Q3/r13 + Q2Q3/r23), where r12, r13, and r23 are the distances between the respective charges. Calculating these distances and substituting the values yields the total potential energy.
How do you calculate the electric potential at a point due to multiple point charges?
The electric potential at a point is the algebraic sum of the potentials due to each individual charge. For each charge, the potential is V = kQ/r, where Q is the charge and r is the distance from the charge to the point. Summing these for all charges gives the total potential at that point.
What is the significance of the distances between charges in determining the electric field and potential?
Distances between charges determine the magnitude of their mutual electrostatic interactions. The electric field strength and potential at a point depend inversely on the distance from each charge (1/r dependence). Closer charges exert stronger influence, so understanding their positions is essential for accurate calculations.
How would the electric field change if the charge Q3 were positive instead of negative?
If Q3 were positive, it would produce an electric field radiating outward, similar to Q1 and Q2. This change would alter the vector sum of the fields at various points, potentially increasing the net field in some regions or changing the direction of the resultant field, especially near Q3.