The Density Of A 3.539 M HNO3 Aqueous Solution Is 1.150 G/ml. At 20C. Calculate The Molality Of The Solution.

The Density Of A 3.539 M HNO3 Aqueous Solution Is 1.150 G/ml. At 20C. Calculate The Molality Of The Solution.

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Understanding the Problem

In this article, we will explore how to determine the molality of a nitric acid (HNO₃) aqueous solution given specific data points. The problem provides the molarity (3.539 M), the density of the solution (1.150 g/mL), and the temperature at which measurements are taken (20°C). Our goal is to calculate the molality, which is a measure of concentration expressing moles of solute per kilogram of solvent.

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Key Concepts and Definitions

Before delving into the calculation, it's important to understand some fundamental concepts:

What is Molarity (M)?

  • Molarity is defined as the number of moles of solute (HNO₃) per liter of solution.
  • Expressed as mol/L.

What is Density?

  • Density (\(\rho\)) is mass per unit volume, typically expressed as g/mL or g/L.
  • In this case, the density of the solution is 1.150 g/mL.

What is Molality (m)?

  • Molality is the number of moles of solute per kilogram of solvent.
  • Expressed as mol/kg.

Why is Molality Important?

  • Molality is temperature-independent because it depends on mass, which doesn't change with temperature.
  • Useful in colligative property calculations.
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Step-by-Step Calculation of Molality

To find the molality, we need to determine:


  • The mass of the solution per liter.

  • The mass of HNO₃ in that liter.

  • The mass of the solvent (water) in that liter.

  • The number of moles of HNO₃.


Let's proceed step-by-step.

1. Calculate the mass of 1 liter of the solution

Given the density:

\[
\text{Mass of 1 L of solution} = \text{Density} \times \text{Volume}
\]

Since 1 L = 1000 mL:

\[
\text{Mass} = 1.150\, \text{g/mL} \times 1000\, \text{mL} = 1150\, \text{g}
\]

So, each liter of the solution weighs 1150 grams.

2. Determine the number of moles of HNO₃ in 1 liter

Given molarity:

\[
\text{Moles of HNO}_3 = 3.539\, \text{mol/L}
\]

This means in 1 liter of solution, there are 3.539 moles of HNO₃.

3. Calculate the mass of HNO₃ in 1 liter

The molar mass of HNO₃:

\[
\text{H} = 1.008\, \text{g/mol} \\
\text{N} = 14.007\, \text{g/mol} \\
\text{O}_3 = 3 \times 16.00\, \text{g/mol} = 48.00\, \text{g/mol}
\]

Total molar mass of HNO₃:

\[
1.008 + 14.007 + 48.00 = 63.015\, \text{g/mol}
\]

Mass of HNO₃ in 1 liter:

\[
\text{Mass} = 3.539\, \text{mol} \times 63.015\, \text{g/mol} \approx 223.2\, \text{g}
\]

4. Find the mass of water (solvent) in 1 liter

Total mass of solution:

\[
1150\, \text{g}
\]

Mass of HNO₃:

\[
223.2\, \text{g}
\]

Therefore, the mass of water:

\[
\text{Mass of water} = 1150\, \text{g} - 223.2\, \text{g} = 926.8\, \text{g}
\]

Convert this to kilograms:

\[
926.8\, \text{g} = 0.9268\, \text{kg}
\]

5. Calculate molality

Molality (\(m\)) is:

\[
m = \frac{\text{moles of solute}}{\text{kg of solvent}}
\]

Substituting the known values:

\[
m = \frac{3.539\, \text{mol}}{0.9268\, \text{kg}} \approx 3.82\, \text{mol/kg}
\]

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Final Answer

The molality of the 3.539 M HNO₃ aqueous solution at 20°C is approximately 3.82 mol/kg.

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Additional Insights and Applications

Understanding how to convert between different concentration units is vital in chemistry, especially when preparing solutions or analyzing experimental data. Here are some key applications:

1. Comparing Concentration Measures

  • Molarity and molality are two common ways to express solution concentration.
  • Molarity varies with temperature due to volume changes, whereas molality remains constant.

2. Practical Uses in Laboratory Settings

  • Molality is often preferred when temperature stability is crucial, such as in colligative property measurements like boiling point elevation or freezing point depression.

3. Safety and Handling of Nitric Acid

  • Nitric acid is a highly corrosive and reactive acid.
  • Proper understanding of concentration helps in safe handling and accurate dilution procedures.

4. Calculations in Industrial Applications

  • Precise concentration calculations are essential in manufacturing processes involving nitric acid, such as in fertilizers, explosives, and chemical syntheses.
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Conclusion

Calculating the molality of a solution from molarity and density involves understanding the relationships between mass, volume, and moles. In our case, starting from the known molarity and density, we determined the total mass of solution, the mass of solute (HNO₃), and the mass of solvent (water). Ultimately, we found that the molality of the solution is approximately 3.82 mol/kg, a concentration measure critical for various scientific and industrial applications.

By mastering such calculations, chemists can accurately prepare solutions, interpret experimental data, and ensure safety and precision in laboratory and industrial processes.

Frequently Asked Questions

What is the given molarity of the HNO3 solution in the problem?
The molarity of the HNO3 solution is 3.539 M.
What is the density of the HNO3 aqueous solution at 20°C?
The density of the solution is 1.150 g/mL.
How do you convert the density from g/mL to g/L for calculations?
Since 1 mL = 0.001 L, multiply the density in g/mL by 1000 to get g/L, so 1.150 g/mL equals 1150 g/L.
What is the definition of molality in solution chemistry?
Molality is defined as the number of moles of solute per kilogram of solvent.
How can we determine the molality of the HNO3 solution given its molarity and density?
By calculating the mass of solution per liter, the mass of HNO3 from molarity, and then subtracting to find solvent mass, we can find molality using the moles of solute and solvent mass in kg.
What is the step-by-step approach to compute the molality of this HNO3 solution?
First, find the mass of 1 L of solution using density (1150 g). Then, determine the mass of HNO3 using molarity (3.539 mol/L), calculate the mass of the solute, find the mass of solvent by subtracting, convert solvent mass to kg, and finally divide moles of solute by solvent kg to get molality.
What is the approximate molality of the 3.539 M HNO3 solution with given density at 20°C?
The approximate molality is about 3.9 mol/kg, calculated by the steps of converting solution mass, determining solute and solvent masses, and dividing moles by solvent in kilograms.